What is 6\div (2(1+2)) ?

The solution to 6\div (2(1+2)) is 1

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6\div (2(1+2))

6 \div (2 (1 + 2))

1

Solution steps

6 \div (2 (1 + 2))

Follow the PEMDAS order of operations

Calculate within parentheses

(2 (1 + 2)) : 6

2 (1 + 2)

Calculate within parentheses

(1 + 2) : 3

1 + 2

1 + 2 = 3

= 3

= 2 \cdot 3

Multiply and divide (left to right)

2 \cdot 3 : 6

2 \cdot 3

2 \cdot 3 = 6

= 6

= 6

= 6 \div 6

Multiply and divide (left to right)

6 \div 6 : 1

6 \div 6

6 \div 6 = 1

= 1

= 1

6 \cdot 6^{4}

2 \times 2^{3}

2 (5)^{2} - (- 1)^{2} - 3 (2)^{2}

- 5 \times 4 \div 10

2 (0) + 4