What is (2^0-(-2)^2)/(2^2+(-2)^3) ?

The solution to (2^0-(-2)^2)/(2^2+(-2)^3) is 3/4

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(2^0-(-2)^2)/(2^2+(-2)^3)

\frac{2 ^{0} - ( - 2 ) ^{2}}{2 ^{2} + ( - 2 ) ^{3}}

\frac{3}{4}

Solution steps

\frac{2 ^{0} - ( - 2 ) ^{2}}{2 ^{2} + ( - 2 ) ^{3}}

Solve

2^{0} - (- 2)^{2} : - 3

Follow the PEMDAS order of operations

Calculate exponents

2^{0} : 1

2^{0}

2^{0} = 1

= 1

= 1 - (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 1 - 4

Add and subtract (left to right)

1 - 4 : - 3

1 - 4

1 - 4 = - 3

= - 3

= - 3

Solve

2^{2} + (- 2)^{3} : - 4

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 + (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 4 - 8

Add and subtract (left to right)

4 - 8 : - 4

4 - 8

4 - 8 = - 4

= - 4

= - 4

= \frac{- 3}{- 4}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{3}{4}

6^{2} + 1 0^{2}

1^{2} + 2^{2} + 3^{2}

2 \times 4^{2}

15 \cdot 8 - (3 \cdot 5) \div (- 3) + 4 \cdot (- 3) + 1

\frac{8}{2 ( 2 + 2 )}

What is (2^0-(-2)^2)/(2^2+(-2)^3) ?
The solution to (2^0-(-2)^2)/(2^2+(-2)^3) is 3/4