What is (3+1/4)(1-4/5) ?

The solution to (3+1/4)(1-4/5) is 13/20

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(3+1/4)(1-4/5)

(3 + \frac{1}{4}) (1 - \frac{4}{5})

\frac{13}{20}

Solution steps

(3 + \frac{1}{4}) (1 - \frac{4}{5})

Follow the PEMDAS order of operations

Calculate within parentheses

(3 + \frac{1}{4}) : \frac{13}{4}

3 + \frac{1}{4}

3 + \frac{1}{4} = \frac{13}{4}

3 + \frac{1}{4}

Convert element to fraction:

3 = \frac{3 \cdot 4}{4}

= \frac{3 \cdot 4}{4} + \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 4 + 1}{4}

3 \cdot 4 + 1 = 13

3 \cdot 4 + 1

Multiply the numbers:

3 \cdot 4 = 12

= 12 + 1

Add the numbers:

12 + 1 = 13

= 13

= \frac{13}{4}

= \frac{13}{4}

= \frac{13}{4} (1 - \frac{4}{5})

Calculate within parentheses

(1 - \frac{4}{5}) : \frac{1}{5}

1 - \frac{4}{5}

1 - \frac{4}{5} = \frac{1}{5}

1 - \frac{4}{5}

Convert element to fraction:

1 = \frac{1 \cdot 5}{5}

= \frac{1 \cdot 5}{5} - \frac{4}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 5 - 4}{5}

1 \cdot 5 - 4 = 1

1 \cdot 5 - 4

Multiply the numbers:

1 \cdot 5 = 5

= 5 - 4

Subtract the numbers:

5 - 4 = 1

= 1

= \frac{1}{5}

= \frac{1}{5}

= \frac{13}{4} \cdot \frac{1}{5}

Multiply and divide (left to right)

\frac{13}{4} \cdot \frac{1}{5} : \frac{13}{20}

\frac{13}{4} \cdot \frac{1}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{13 \cdot 1}{4 \cdot 5}

Multiply the numbers:

13 \cdot 1 = 13

= \frac{13}{4 \cdot 5}

Multiply the numbers:

4 \cdot 5 = 20

= \frac{13}{20}

= \frac{13}{20}

1^{2} - 4

1^{2} + 1

1 2^{2} + 9^{2}

3 (0)^{2}

350 - 2 - 125 + 4 - (31 - 30) - (7 - 1) - (5 - 4 + 1)