What is (-2)^3+(-3)^2-(-1)^2-(-2)^5 ?

The solution to (-2)^3+(-3)^2-(-1)^2-(-2)^5 is 32

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(-2)^3+(-3)^2-(-1)^2-(-2)^5

(- 2)^{3} + (- 3)^{2} - (- 1)^{2} - (- 2)^{5}

32

Solution steps

(- 2)^{3} + (- 3)^{2} - (- 1)^{2} - (- 2)^{5}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 + (- 3)^{2} - (- 1)^{2} - (- 2)^{5}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= - 8 + 9 - (- 1)^{2} - (- 2)^{5}

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 8 + 9 - 1 - (- 2)^{5}

Calculate exponents

(- 2)^{5} : - 32

(- 2)^{5}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{5} = - 2^{5} = - 32

= - 32

= - 8 + 9 - 1 - (- 32)

Add and subtract (left to right)

- 8 + 9 - 1 - (- 32) : 32

- 8 + 9 - 1 - (- 32)

- 8 + 9 = 1

= 1 - 1 - (- 32)

1 - 1 = 0

= 0 - (- 32)

Apply rule

- (- a) = + a

- (- 32) = + 32

= 0 + 32

0 + 32 = 32

= 32

= 32

8^{2} + 6^{2}

3^{2} + 5^{2}

(- 1)^{0} - (- 1^{0})

1 7^{2} - 1 5^{2}

5^{2} + 5^{2}

What is (-2)^3+(-3)^2-(-1)^2-(-2)^5 ?
The solution to (-2)^3+(-3)^2-(-1)^2-(-2)^5 is 32