What is ((x-3)^2)/(81)-((y+5)^2)/(144)=1 ?

The solution to ((x-3)^2)/(81)-((y+5)^2)/(144)=1 is Hyperbola with (h,k)=(3,-5),a=9,b=12

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((x-3)^2)/(81)-((y+5)^2)/(144)=1

\frac{( x - 3 ) ^{2}}{81} - \frac{( y + 5 ) ^{2}}{144} = 1

(h, k) = (3, - 5), a = 9, b = 12

Solution steps

\frac{( x - 3 ) ^{2}}{81} - \frac{( y + 5 ) ^{2}}{144} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{81} - \frac{( y + 5 ) ^{2}}{144} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{9 ^{2}} - \frac{( y - ( - 5 ) ) ^{2}}{1 2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 5), a = 9, b = 12

x = \frac{1}{4} y^{2}

x^{2} + y^{2} - 4 y = 0

x^{2} = - 8 y

f (x) = (x - 3)^{2}

x^{2} + 9 y^{2} + 6 x - 90 y + 225 = 0

What is ((x-3)^2)/(81)-((y+5)^2)/(144)=1 ?
The solution to ((x-3)^2)/(81)-((y+5)^2)/(144)=1 is Hyperbola with (h,k)=(3,-5),a=9,b=12