What is ((x-1)^2)/(16)+((y-2)^2)/(49)=1 ?

The solution to ((x-1)^2)/(16)+((y-2)^2)/(49)=1 is Ellipse with (h,k)=(1,2),a=4,b=7

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((x-1)^2)/(16)+((y-2)^2)/(49)=1

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{49} = 1

(h, k) = (1, 2), a = 4, b = 7

Solution steps

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{49} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{4 ^{2}} + \frac{( y - 2 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 2), a = 4, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, 2), b = 7, a = 4

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17 x^{2} + 16 y^{2} - 102 x - 32 y - 103 = 0

x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0

2 y - xx - yy > 0

2 x^{2} + 4 y^{2} + 8 x + 9 y - 3 = 0

What is ((x-1)^2)/(16)+((y-2)^2)/(49)=1 ?
The solution to ((x-1)^2)/(16)+((y-2)^2)/(49)=1 is Ellipse with (h,k)=(1,2),a=4,b=7