What is (x/2)^2+(y)^2=1 ?

The solution to (x/2)^2+(y)^2=1 is Ellipse with (h,k)=(0,0),a=2,b=1

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(x/2)^2+(y)^2=1

(\frac{x}{2})^{2} + (y)^{2} = 1

(h, k) = (0, 0), a = 2, b = 1

Solution steps

(\frac{x}{2})^{2} + y^{2} = 1

Rewrite

(\frac{x}{2})^{2} + y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 1

3 x^{2} + y^{2} + 2 y - 8 = 0

\frac{( x - 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{16} = 1

x^{2} + y^{2} + 10 y = 0

12 x^{2} + 96 x + 5 y^{2} + 50 y + 257 = 0

\frac{( x - 3 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{3} = 1

What is (x/2)^2+(y)^2=1 ?
The solution to (x/2)^2+(y)^2=1 is Ellipse with (h,k)=(0,0),a=2,b=1