What is x^2+(8-6)y^2=1 ?

The solution to x^2+(8-6)y^2=1 is Ellipse with (h,k)=(0,0),a=1,b=sqrt(1/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+(8-6)y^2=1

x^{2} + (8 - 6) y^{2} = 1

(h, k) = (0, 0), a = 1, b = \frac{1}{2}

Solution steps

x^{2} + (8 - 6) y^{2} = 1

Rewrite

x^{2} + (8 - 6) y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{1}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = \frac{1}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 1, b = \frac{1}{2}

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 5 ) ^{2}}{9} = 1

\frac{100}{1 + x ^{2} + 2 y ^{2}} = 1

81 x^{2} + 49 y^{2} + 486 x - 490 y - 2015 = 0

0 = 1 + 2 x^{2} + 2 y^{2}

4 x^{2} + y^{2} + 8 x - 4 y - 8 = 0

What is x^2+(8-6)y^2=1 ?
The solution to x^2+(8-6)y^2=1 is Ellipse with (h,k)=(0,0),a=1,b=sqrt(1/2)