What is x^2-6x+2y^2+4y-11=0 ?

The solution to x^2-6x+2y^2+4y-11=0 is Ellipse with (h,k)=(3,-1),a=sqrt(22),b=sqrt(11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-6x+2y^2+4y-11=0

x^{2} - 6 x + 2 y^{2} + 4 y - 11 = 0

(h, k) = (3, - 1), a = 22, b = 11

Solution steps

x^{2} - 6 x + 2 y^{2} + 4 y - 11 = 0

Rewrite

x^{2} - 6 x + 2 y^{2} + 4 y - 11 = 0

in the form of the standard ellipse equation

\frac{( x - 3 ) ^{2}}{( 22 ) ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{( 11 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (3, - 1), a = 22, b = 11

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (3, - 1), a = 22, b = 11

18 x^{2} + 9 y^{2} = 9

x^{2} + y^{2} - 5 y = 0

36 x^{2} + y^{2} + 2 y + 1 = 9

(4 x^{2}) + (y^{2}) - 8 x - 4 y - 28 = 0

112 x^{2} + 144 y^{2} - 896 x + 864 y = - 2080

What is x^2-6x+2y^2+4y-11=0 ?
The solution to x^2-6x+2y^2+4y-11=0 is Ellipse with (h,k)=(3,-1),a=sqrt(22),b=sqrt(11)