What is (x^2)/(25)+(z^2)/(64)=1 ?

The solution to (x^2)/(25)+(z^2)/(64)=1 is Ellipse with (h,k)=(0,0),a=5,b=8

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(x^2)/(25)+(z^2)/(64)=1

\frac{x ^{2}}{25} + \frac{z ^{2}}{64} = 1

(h, k) = (0, 0), a = 5, b = 8

Solution steps

\frac{x ^{2}}{25} + \frac{z ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{z ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( z - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 8, a = 5

\frac{x ^{2}}{4} + \frac{3 y ^{2}}{4} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{1} = 1

x^{2} + 4 y^{2} + 20 x - 40 y = - 100

\frac{x ^{2}}{9} + \frac{y ^{2}}{64} = 1

4 x^{2} + 3 y^{2} + 24 x + 36 y + 72 = 0

What is (x^2)/(25)+(z^2)/(64)=1 ?
The solution to (x^2)/(25)+(z^2)/(64)=1 is Ellipse with (h,k)=(0,0),a=5,b=8