What is the radius (x-5)^2+(y+2)^2=16 ?

The radius (x-5)^2+(y+2)^2=16 is r=4

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radius (x-5)^2+(y+2)^2=16

radius

(x - 5)^{2} + (y + 2)^{2} = 16

r = 4

Solution steps

(x - 5)^{2} + (y + 2)^{2} = 16

Rewrite

(x - 5)^{2} + (y + 2)^{2} = 16

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (5, - 2), r = 4

And the radius is:

r = 4

x^{2} - 6 x + y^{2} - 8 y = 0

(x + 5)^{2} + (y - 6)^{2} = 4

5 x^{2} + 5 y^{2} + 10 x - 5 y + 3 = 0

x^{2} + y^{2} - 2 x - 15 = 0

x^{2} + y^{2} - 4 x + 2 y - 11 = 0