What is the radius x^2+(y-3)^2=25 ?

The radius x^2+(y-3)^2=25 is r=5

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radius x^2+(y-3)^2=25

radius

x^{2} + (y - 3)^{2} = 25

r = 5

Solution steps

x^{2} + (y - 3)^{2} = 25

Rewrite

x^{2} + (y - 3)^{2} = 25

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 5

And the radius is:

r = 5

x^{2} + y^{2} + 6 x - 4 y = 0

x^{2} + y^{2} = 6

x^{2} + y^{2} = 5

x^{2} + y^{2} = 8

36 x^{2} + 36 y^{2} - 12 x - 27 y - 8 = 0