What is the radius x^2+y^2+12x-12y+36=0 ?

The radius x^2+y^2+12x-12y+36=0 is r=6

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radius x^2+y^2+12x-12y+36=0

radius

x^{2} + y^{2} + 12 x - 12 y + 36 = 0

r = 6

Solution steps

x^{2} + y^{2} + 12 x - 12 y + 36 = 0

Rewrite

x^{2} + y^{2} + 12 x - 12 y + 36 = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 6)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 6, 6), r = 6

And the radius is:

r = 6

x^{2} + y^{2} + 6 x - 4 y - 12 = 0

x^{2} + y^{2} = 2

x^{2} + y^{2} - 8 x - 6 y - 11 = 0

5 x^{2} + 5 y^{2} + 10 x - 20 y = 55

(x - 1)^{2} + y^{2} = 1

What is the radius x^2+y^2+12x-12y+36=0 ?
The radius x^2+y^2+12x-12y+36=0 is r=6