What is the center x^2+y^2-10x+16y+85=0 ?

The center x^2+y^2-10x+16y+85=0 is (5,-8)

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center x^2+y^2-10x+16y+85=0

center

x^{2} + y^{2} - 10 x + 16 y + 85 = 0

(5, - 8)

Solution steps

x^{2} + y^{2} - 10 x + 16 y + 85 = 0

Rewrite

x^{2} + y^{2} - 10 x + 16 y + 85 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 8))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (5, - 8), r = 2

And the center is:

(5, - 8)

x^{2} + y^{2} - 2 x - 1 y - 4 = 0

x^{2} - 18 x + 53 = - y^{2} + 12 y

x^{2} + y^{2} + 2 y - 24 = 0

x^{2} + y^{2} + 10 x + 8 y - 4 = 0

x^{2} + (y - 7)^{2} = 36

What is the center x^2+y^2-10x+16y+85=0 ?
The center x^2+y^2-10x+16y+85=0 is (5,-8)