Solution
center
Solution
Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:
Popular Examples
center (x+1)^2+(y+2)^2=25center center x^2+y^2-20x+64y-371=0center center 4x^2+4y^2-8y-5=0center center (x-1)^2+(y-4)^2=9center center 2x^2+2y^2-4x+12y-12=0center
Frequently Asked Questions (FAQ)
What is the center x^2+y^2=289 ?
The center x^2+y^2=289 is (0,0)