What is the center (x^2)/(49)+(y^2)/(49)=1 ?

The center (x^2)/(49)+(y^2)/(49)=1 is (0,0)

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center (x^2)/(49)+(y^2)/(49)=1

center

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{49} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 7

And the center is:

(0, 0)

(x + 2)^{2} + (y - 2)^{2} = 20

4 x^{2} - 40 x + 4 y^{2} - 32 y = 5

x^{2} + y^{2} - 2 x + 4 y = 0

x^{2} + y^{2} + 2 x + 4 y - 20 = 0

2 x^{2} + 2 y^{2} + 8 x + 16 y + 14 = 0

What is the center (x^2)/(49)+(y^2)/(49)=1 ?
The center (x^2)/(49)+(y^2)/(49)=1 is (0,0)