What is the center (x+5)^2+(y-2)^2=15 ?

The center (x+5)^2+(y-2)^2=15 is (-5,2)

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center (x+5)^2+(y-2)^2=15

center

(x + 5)^{2} + (y - 2)^{2} = 15

(- 5, 2)

Solution steps

(x + 5)^{2} + (y - 2)^{2} = 15

Rewrite

(x + 5)^{2} + (y - 2)^{2} = 15

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 2)^{2} = (15)^{2}

Therefore the circle properties are:

(a, b) = (- 5, 2), r = 15

And the center is:

(- 5, 2)

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