What is 2x^2+3x+2y^2+7y=57.75 ?

The solution to 2x^2+3x+2y^2+7y=57.75 is Circle with (a,b)=(-3/4 ,-7/4),r=5.70087…

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2x^2+3x+2y^2+7y=57.75

2 x^{2} + 3 x + 2 y^{2} + 7 y = 57.75

(a, b) = (- \frac{3}{4}, - \frac{7}{4}), r = 5.70087 \dots

Solution steps

2 x^{2} + 3 x + 2 y^{2} + 7 y = 57.75

Rewrite

2 x^{2} + 3 x + 2 y^{2} + 7 y = 57.75

in the form of the standard circle equation

(x - (- \frac{3}{4}))^{2} + (y - (- \frac{7}{4}))^{2} = 5.70087 \dots^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{4}, - \frac{7}{4}), r = 5.70087 \dots

x^{2} + y^{2} - 4 x + 8 y = 0

(x - (- 1))^{2} + (y - 3)^{2} = (3)^{2}

(x - 6)^{2} + (y + 5)^{2} = 4^{2}

x^{2} + y^{2} - 2 x + 6 y - 90 = 0

4 (x + 3)^{2} + 4 (y - 0)^{2} = 16

What is 2x^2+3x+2y^2+7y=57.75 ?
The solution to 2x^2+3x+2y^2+7y=57.75 is Circle with (a,b)=(-3/4 ,-7/4),r=5.70087…