What is (x+7)^2+y^2=16 ?

The solution to (x+7)^2+y^2=16 is Circle with (a,b)=(-7,0),r=4

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(x+7)^2+y^2=16

(x + 7)^{2} + y^{2} = 16

(a, b) = (- 7, 0), r = 4

Solution steps

(x + 7)^{2} + y^{2} = 16

Rewrite

(x + 7)^{2} + y^{2} = 16

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 7, 0), r = 4

(x + 1)^{2} + (y - 1)^{2} = 9 (x - 2)^{2} + 9 (y + 1)^{2}

(x - 9)^{2} + (y - 8)^{2} = 81

x^{2} + y^{2} - 16 x + 8 y + 55 = 0

x^{2} + y^{2} - 10 x + 14 y - 7 = 0

x^{2} + y^{2} = 47 + 3 x

What is (x+7)^2+y^2=16 ?
The solution to (x+7)^2+y^2=16 is Circle with (a,b)=(-7,0),r=4