What is (x+6)^2+(y-4)^2=73 ?

The solution to (x+6)^2+(y-4)^2=73 is Circle with (a,b)=(-6,4),r=sqrt(73)

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(x+6)^2+(y-4)^2=73

(x + 6)^{2} + (y - 4)^{2} = 73

(a, b) = (- 6, 4), r = 73

Solution steps

(x + 6)^{2} + (y - 4)^{2} = 73

Rewrite

(x + 6)^{2} + (y - 4)^{2} = 73

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 4)^{2} = (73)^{2}

Therefore the circle properties are:

(a, b) = (- 6, 4), r = 73

(3)^{2} = (x - 2)^{2} + (y - (- 3))^{2}

(x + 10)^{2} + (y + 9)^{2} = 36

x^{2} + 3 x + y^{2} + 7 y - 1 = 0

(x - 9)^{2} + (y - 8)^{2} = 64

(x + \frac{1}{2})^{2} + (y - 5)^{2} = \frac{25}{4}

What is (x+6)^2+(y-4)^2=73 ?
The solution to (x+6)^2+(y-4)^2=73 is Circle with (a,b)=(-6,4),r=sqrt(73)