What is (x-2)^2+(y+1)^2=13 ?

The solution to (x-2)^2+(y+1)^2=13 is Circle with (a,b)=(2,-1),r=sqrt(13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-2)^2+(y+1)^2=13

(x - 2)^{2} + (y + 1)^{2} = 13

(a, b) = (2, - 1), r = 13

Solution steps

(x - 2)^{2} + (y + 1)^{2} = 13

Rewrite

(x - 2)^{2} + (y + 1)^{2} = 13

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 1))^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (2, - 1), r = 13

(x - \frac{7}{2})^{2} + (y - 1)^{2} = 4.27

x^{2} + 7 x + y^{2} - 8 y = 3

x^{2} + y^{2} + 10 x - 14 y - 70 = 0

(x - 6)^{2} + (y - 3)^{2} = 25

x^{2} + y^{2} - \frac{42}{11} x - \frac{60}{11} y - \frac{164}{11} = 0

What is (x-2)^2+(y+1)^2=13 ?
The solution to (x-2)^2+(y+1)^2=13 is Circle with (a,b)=(2,-1),r=sqrt(13)