What is (x-5)^2+(y-2)^2=49 ?

The solution to (x-5)^2+(y-2)^2=49 is Circle with (a,b)=(5,2),r=7

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(x-5)^2+(y-2)^2=49

(x - 5)^{2} + (y - 2)^{2} = 49

(a, b) = (5, 2), r = 7

Solution steps

(x - 5)^{2} + (y - 2)^{2} = 49

Rewrite

(x - 5)^{2} + (y - 2)^{2} = 49

in the form of the standard circle equation

(x - 5)^{2} + (y - 2)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (5, 2), r = 7

(x - 15)^{2} + [y - (- 20)]^{2} = (9)^{2}

25 = (x + 7)^{2} + (y + 2)^{2}

x^{2} + y^{2} - 7 x + 2 y - 11 = 0

4 x^{2} + 4 y^{2} - 8 x + 32 y + 4 = 0

x^{2} + y^{2} - 4 x + 14 y + 37 = 0

What is (x-5)^2+(y-2)^2=49 ?
The solution to (x-5)^2+(y-2)^2=49 is Circle with (a,b)=(5,2),r=7