What is x^2-4x+y^2+6y=113 ?

The solution to x^2-4x+y^2+6y=113 is Circle with (a,b)=(2,-3),r=3sqrt(14)

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x^2-4x+y^2+6y=113

x^{2} - 4 x + y^{2} + 6 y = 113

(a, b) = (2, - 3), r = 314

Solution steps

x^{2} - 4 x + y^{2} + 6 y = 113

Rewrite

x^{2} - 4 x + y^{2} + 6 y = 113

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = (314)^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 314

x^{2} + y^{2} - 5 x + y - 55 = 0

x^{2} + y^{2} + 20 x + 40 y + 400 = 0

x^{2} + y^{2} - 4 y - 5 = 0

- y^{(2)} + 14 y = x^{(2)} - 10 x + 25 + 49 - 12.24

\frac{x ^{2}}{4} + \frac{z ^{2}}{4} = 1

What is x^2-4x+y^2+6y=113 ?
The solution to x^2-4x+y^2+6y=113 is Circle with (a,b)=(2,-3),r=3sqrt(14)