What is (x+2/5)^2+(y-3/4)^2=3 ?

The solution to (x+2/5)^2+(y-3/4)^2=3 is Circle with (a,b)=(-2/5 , 3/4),r=sqrt(3)

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(x+2/5)^2+(y-3/4)^2=3

(x + \frac{2}{5})^{2} + (y - \frac{3}{4})^{2} = 3

(a, b) = (- \frac{2}{5}, \frac{3}{4}), r = 3

Solution steps

(x + \frac{2}{5})^{2} + (y - \frac{3}{4})^{2} = 3

Rewrite

(x + \frac{2}{5})^{2} + (y - \frac{3}{4})^{2} = 3

in the form of the standard circle equation

(x - (- \frac{2}{5}))^{2} + (y - \frac{3}{4})^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (- \frac{2}{5}, \frac{3}{4}), r = 3

5 x^{2} + 5 y^{2} = 30

(x + 4)^{2} + (y + 0)^{2} = 5

5 x^{2} + 5 y^{2} = 8

(x - 6)^{2} + (y - 5)^{2} = 4^{2}

5 x^{2} + 5 y^{2} = 80

What is (x+2/5)^2+(y-3/4)^2=3 ?
The solution to (x+2/5)^2+(y-3/4)^2=3 is Circle with (a,b)=(-2/5 , 3/4),r=sqrt(3)