What is 3x^2+3y^2+12x+12=18y ?

The solution to 3x^2+3y^2+12x+12=18y is Circle with (a,b)=(-2,3),r=3

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3x^2+3y^2+12x+12=18y

3 x^{2} + 3 y^{2} + 12 x + 12 = 18 y

(a, b) = (- 2, 3), r = 3

Solution steps

3 x^{2} + 3 y^{2} + 12 x + 12 = 18 y

Rewrite

3 x^{2} + 3 y^{2} + 12 x + 12 = 18 y

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 3

x^{2} + y^{2} - 8 x + 10 y + 16 = 0

x^{2} + y^{2} + 2 x - 15 = 0

x^{2} + y^{2} - 14 x + 10 y + 49 = 0

x^{2} + y^{2} - 10 x + 6 y = 0

x^{2} - 2 x + 1 + y^{2} + 4 y + 4 = 25

What is 3x^2+3y^2+12x+12=18y ?
The solution to 3x^2+3y^2+12x+12=18y is Circle with (a,b)=(-2,3),r=3