What is x^2+6x+y^2-7=0 ?

The solution to x^2+6x+y^2-7=0 is Circle with (a,b)=(-3,0),r=4

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x^2+6x+y^2-7=0

x^{2} + 6 x + y^{2} - 7 = 0

(a, b) = (- 3, 0), r = 4

Solution steps

x^{2} + 6 x + y^{2} - 7 = 0

Rewrite

x^{2} + 6 x + y^{2} - 7 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 3, 0), r = 4

x^{2} + 8 x + y^{2} - 4 y + 16 = 0

x^{2} + (y + 14. 5^{2} - 5^{2})^{2} = 14. 5^{2}

x^{2} + 5 x + y^{2} + 9 y - 10 = 0

x^{2} + y^{2} - 4 x - 8 y + 16 = 0

x^{2} + 12 x + y^{2} - 8 y + 27 = 0

What is x^2+6x+y^2-7=0 ?
The solution to x^2+6x+y^2-7=0 is Circle with (a,b)=(-3,0),r=4