What is (x-6)^2+(y-8)^2=10^2 ?

The solution to (x-6)^2+(y-8)^2=10^2 is Circle with (a,b)=(6,8),r=10

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(x-6)^2+(y-8)^2=10^2

(x - 6)^{2} + (y - 8)^{2} = 1 0^{2}

(a, b) = (6, 8), r = 10

Solution steps

(x - 6)^{2} + (y - 8)^{2} = 1 0^{2}

Rewrite

(x - 6)^{2} + (y - 8)^{2} = 1 0^{2}

in the form of the standard circle equation

(x - 6)^{2} + (y - 8)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (6, 8), r = 10

x^{2} + y^{2} + \frac{4 ( x ^{2} + y ^{2} )}{21} = 25

x^{2} + z^{2} - 3 x - 6 z + 8 = 0

(x - 9)^{2} + (y - 12)^{2} = 4 (x^{2} + y^{2})

16 x^{2} + 16 y^{2} + 19 x - 40 y = 315

(x - 2)^{2} + (y - 4)^{2} = 1

What is (x-6)^2+(y-8)^2=10^2 ?
The solution to (x-6)^2+(y-8)^2=10^2 is Circle with (a,b)=(6,8),r=10