What is (x+1.5)^2+(y-1)^2=0.5 ?

The solution to (x+1.5)^2+(y-1)^2=0.5 is Circle with (a,b)=(-1.5,1),r=0.70710…

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(x+1.5)^2+(y-1)^2=0.5

(x + 1.5)^{2} + (y - 1)^{2} = 0.5

(a, b) = (- 1.5, 1), r = 0.70710 \dots

Solution steps

(x + 1.5)^{2} + (y - 1)^{2} = 0.5

Rewrite

(x + 1.5)^{2} + (y - 1)^{2} = 0.5

in the form of the standard circle equation

(x - (- 1.5))^{2} + (y - 1)^{2} = 0.70710 \dots^{2}

Therefore the circle properties are:

(a, b) = (- 1.5, 1), r = 0.70710 \dots

4 = (x + 2)^{2} + (y - 1)^{2}

x^{2} + 4 x + y^{2} - 8 y = - 16

x^{2} + y^{2} + 2 x - 4 y = 44

(x - 3)^{2} + (y + 2)^{2} = 2^{2}

(x - 2)^{2} + (y + 4)^{2} = \frac{144}{25}

What is (x+1.5)^2+(y-1)^2=0.5 ?
The solution to (x+1.5)^2+(y-1)^2=0.5 is Circle with (a,b)=(-1.5,1),r=0.70710…