What is 4x^2+36x+4y^2-24y+36=0 ?

The solution to 4x^2+36x+4y^2-24y+36=0 is Circle with (a,b)=(-9/2 ,3),r= 9/2

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4x^2+36x+4y^2-24y+36=0

4 x^{2} + 36 x + 4 y^{2} - 24 y + 36 = 0

(a, b) = (- \frac{9}{2}, 3), r = \frac{9}{2}

Solution steps

4 x^{2} + 36 x + 4 y^{2} - 24 y + 36 = 0

Rewrite

4 x^{2} + 36 x + 4 y^{2} - 24 y + 36 = 0

in the form of the standard circle equation

(x - (- \frac{9}{2}))^{2} + (y - 3)^{2} = (\frac{9}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{9}{2}, 3), r = \frac{9}{2}

(x + 3)^{2} + (y + 5)^{2} = 28

x^{2} + (y - 2)^{2} = 5

4 (x - 4)^{2} + 4 y^{2} = 36

x^{2} + y^{2} + 30 x + 20 y + 317 = 0

x^{2} + y^{2} = 25 (3.4)

What is 4x^2+36x+4y^2-24y+36=0 ?
The solution to 4x^2+36x+4y^2-24y+36=0 is Circle with (a,b)=(-9/2 ,3),r= 9/2