Solution

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:

Popular Examples

x^2-2x+y^2-8y+1=0(x+5)^2+y^2=36x^2+y^2-4x+4y-1=04x^2+4y^2-6=0x^2+y^2+10x-2y+26=1

Frequently Asked Questions (FAQ)

  • What is x^2+(y-\sqrt[3]{2})^2=1 ?

    The solution to x^2+(y-\sqrt[3]{2})^2=1 is Circle with (a,b)=(0,\sqrt[3]{2}),r=1