What is (x-8)^2+(y-6)^2=10^2 ?

The solution to (x-8)^2+(y-6)^2=10^2 is Circle with (a,b)=(8,6),r=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-8)^2+(y-6)^2=10^2

(x - 8)^{2} + (y - 6)^{2} = 1 0^{2}

(a, b) = (8, 6), r = 10

Solution steps

(x - 8)^{2} + (y - 6)^{2} = 1 0^{2}

Rewrite

(x - 8)^{2} + (y - 6)^{2} = 1 0^{2}

in the form of the standard circle equation

(x - 8)^{2} + (y - 6)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (8, 6), r = 10

(5 (x + 4))^{2} + 25 (y - 2)^{2} = 625

x^{2} + y^{2} - 14 x + 12 y + 76 = 0

x^{2} + y^{2} + 6 x + 24 y + 152 = 0

x^{2} + y^{2} - 3 x + 8 y = 20

x^{2} + y^{2} - 12 x - 10 y + 52 = 0

What is (x-8)^2+(y-6)^2=10^2 ?
The solution to (x-8)^2+(y-6)^2=10^2 is Circle with (a,b)=(8,6),r=10