What is (x-0)^{(2)}+(y-0)^{(2)}=3sqrt(2)^2 ?

The solution to (x-0)^{(2)}+(y-0)^{(2)}=3sqrt(2)^2 is Circle with (a,b)=(0,0),r=sqrt(3(\sqrt{2))^2}

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(x-0)^{(2)}+(y-0)^{(2)}=3sqrt(2)^2

(x - 0)^{(2)} + (y - 0)^{(2)} = 3 2^{2}

(a, b) = (0, 0), r = 3 (2)^{2}

Solution steps

(x - 0)^{2} + (y - 0)^{2} = 3 (2)^{2}

Rewrite

(x - 0)^{2} + (y - 0)^{2} = 3 2^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (3 (2)^{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 3 (2)^{2}

y^{2} = 5 0^{2} - x^{2}

x^{2} + y^{2} - 2 x + 6 y + 5 = 0

x^{2} + y^{2} - 2 y - 24 = 0

3 x^{2} + 3 y^{2} - 12 - 8 = 0

(x - 2)^{2} + (y + 7)^{2} = 1

What is (x-0)^{(2)}+(y-0)^{(2)}=3sqrt(2)^2 ?
The solution to (x-0)^{(2)}+(y-0)^{(2)}=3sqrt(2)^2 is Circle with (a,b)=(0,0),r=sqrt(3(\sqrt{2))^2}