What is 3x^2+3y^2-9x+10y-71/12 =0 ?

The solution to 3x^2+3y^2-9x+10y-71/12 =0 is Circle with (a,b)=(3/2 ,-5/3),r=sqrt(7)

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3x^2+3y^2-9x+10y-71/12 =0

3 x^{2} + 3 y^{2} - 9 x + 10 y - \frac{71}{12} = 0

(a, b) = (\frac{3}{2}, - \frac{5}{3}), r = 7

Solution steps

3 x^{2} + 3 y^{2} - 9 x + 10 y - \frac{71}{12} = 0

Rewrite

3 x^{2} + 3 y^{2} - 9 x + 10 y - \frac{71}{12} = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- \frac{5}{3}))^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - \frac{5}{3}), r = 7

4 x^{2} + 4 y^{2} - 24 x - 13 = 0

(x + 5)^{2} + (y + 2)^{2} = 16

(x - 5)^{2} + (y - 3)^{2} = 3^{2}

x^{2} + y^{2} - 2 y - 3 = 0

x^{2} - 4 x + y^{2} - 4 y = 0

What is 3x^2+3y^2-9x+10y-71/12 =0 ?
The solution to 3x^2+3y^2-9x+10y-71/12 =0 is Circle with (a,b)=(3/2 ,-5/3),r=sqrt(7)