What is x^2+y^2+2y=15 ?

The solution to x^2+y^2+2y=15 is Circle with (a,b)=(0,-1),r=4

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x^2+y^2+2y=15

x^{2} + y^{2} + 2 y = 15

(a, b) = (0, - 1), r = 4

Solution steps

x^{2} + y^{2} + 2 y = 15

Rewrite

x^{2} + y^{2} + 2 y = 15

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 1))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, - 1), r = 4

x^{(2)} + y^{(2)} - 6 x + 8 y + 6 = 0

(x + 3)^{2} + (y - 7)^{2} = 58

\frac{( 9 )}{( 2 )} x^{(2)} + \frac{( 9 )}{( 2 )} y^{(2)} = 1

(x)^{2} + (y - 5)^{2} = 4

x^{2} + y^{2} - 10 x + 4 y - 56 = 0

What is x^2+y^2+2y=15 ?
The solution to x^2+y^2+2y=15 is Circle with (a,b)=(0,-1),r=4