What is y^2=-x^2+4x ?

The solution to y^2=-x^2+4x is Circle with (a,b)=(2,0),r=2

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y^2=-x^2+4x

y^{2} = - x^{2} + 4 x

(a, b) = (2, 0), r = 2

Solution steps

y^{2} = - x^{2} + 4 x

Rewrite

y^{2} = - x^{2} + 4 x

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 2

x^{2} + y^{2} - 6 x - 12 y - 55 = 0

(x - 3)^{2} + (y + 2)^{2} = 32

x^{2} + y^{2} - 2 x - 2 y - 13 = 0

(x - 8)^{2} + (y + 2)^{2} = 49

4 x^{2} + 4 y^{2} + 24 x - 16 y - 52 = 0

What is y^2=-x^2+4x ?
The solution to y^2=-x^2+4x is Circle with (a,b)=(2,0),r=2