What is x^2+9x+y^2-5y-7=0 ?

The solution to x^2+9x+y^2-5y-7=0 is Circle with (a,b)=(-9/2 , 5/2),r=sqrt(67/2)

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x^2+9x+y^2-5y-7=0

x^{2} + 9 x + y^{2} - 5 y - 7 = 0

(a, b) = (- \frac{9}{2}, \frac{5}{2}), r = \frac{67}{2}

Solution steps

x^{2} + 9 x + y^{2} - 5 y - 7 = 0

Rewrite

x^{2} + 9 x + y^{2} - 5 y - 7 = 0

in the form of the standard circle equation

(x - (- \frac{9}{2}))^{2} + (y - \frac{5}{2})^{2} = (\frac{67}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{9}{2}, \frac{5}{2}), r = \frac{67}{2}

x^{2} + y^{2} - 2 x = 1

(x - 4)^{2} + (y - 5)^{2} = 4

(x - 4)^{2} + (y - 5)^{2} = 2

x^{2} - 8 x + y^{2} - 2 y = 8

100 x^{2} + 100 y^{2} - 100 x + 240 y - 56 = 0

What is x^2+9x+y^2-5y-7=0 ?
The solution to x^2+9x+y^2-5y-7=0 is Circle with (a,b)=(-9/2 , 5/2),r=sqrt(67/2)