What is 9x^2+9y^2-16x+18y-11=0 ?

The solution to 9x^2+9y^2-16x+18y-11=0 is Circle with (a,b)=(8/9 ,-1),r=(2sqrt(61))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9x^2+9y^2-16x+18y-11=0

9 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

(a, b) = (\frac{8}{9}, - 1), r = \frac{2 61}{9}

Solution steps

9 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

Rewrite

9 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

in the form of the standard circle equation

(x - \frac{8}{9})^{2} + (y - (- 1))^{2} = (\frac{2 61}{9})^{2}

Therefore the circle properties are:

(a, b) = (\frac{8}{9}, - 1), r = \frac{2 61}{9}

x^{2} + (z - 1)^{2} = 1

x^{2} + y^{2} - 6 x + 10 y + 30 = 0

(x - 3)^{2} + (y + 1)^{2} = 10

y^{2} + x^{2} + 8 x = 0

y^{2} + x^{2} = 8

What is 9x^2+9y^2-16x+18y-11=0 ?
The solution to 9x^2+9y^2-16x+18y-11=0 is Circle with (a,b)=(8/9 ,-1),r=(2sqrt(61))/9