What is 3x^2+3y^2+54x-36y-156=0 ?

The solution to 3x^2+3y^2+54x-36y-156=0 is Circle with (a,b)=(-9,6),r=13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2+3y^2+54x-36y-156=0

3 x^{2} + 3 y^{2} + 54 x - 36 y - 156 = 0

(a, b) = (- 9, 6), r = 13

Solution steps

3 x^{2} + 3 y^{2} + 54 x - 36 y - 156 = 0

Rewrite

3 x^{2} + 3 y^{2} + 54 x - 36 y - 156 = 0

in the form of the standard circle equation

(x - (- 9))^{2} + (y - 6)^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (- 9, 6), r = 13

(- x - 3)^{2} + (y - 2)^{2} = 2^{2}

x^{2} + y^{2} - 4 x + 6 y = 23

(x - (- 2))^{2} + (y - 5)^{2} = 4^{2}

x^{2} - 3 x + y^{2} + 2 y - 14 = 0

x^{2} + y^{2} + 14 x - 8 y + 56 = 0

What is 3x^2+3y^2+54x-36y-156=0 ?
The solution to 3x^2+3y^2+54x-36y-156=0 is Circle with (a,b)=(-9,6),r=13