What is (x-1)^2+(y-3)^2=64 ?

The solution to (x-1)^2+(y-3)^2=64 is Circle with (a,b)=(1,3),r=8

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(x-1)^2+(y-3)^2=64

(x - 1)^{2} + (y - 3)^{2} = 64

(a, b) = (1, 3), r = 8

Solution steps

(x - 1)^{2} + (y - 3)^{2} = 64

Rewrite

(x - 1)^{2} + (y - 3)^{2} = 64

in the form of the standard circle equation

(x - 1)^{2} + (y - 3)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (1, 3), r = 8

2 x^{2} + 2 y^{2} + 12 y + 10 = 0

(x - 7)^{(2)} + (y + 15)^{(2)} = 200

x^{2} + (y - 3)^{2} = 2.6

16 x^{2} + 96 x + 16 y^{2} - 14 y = 315

3 x^{2} + 3 y^{2} - 18 x - 30 y - 6 = 0

What is (x-1)^2+(y-3)^2=64 ?
The solution to (x-1)^2+(y-3)^2=64 is Circle with (a,b)=(1,3),r=8