What is x^2+5x+y^2-7y+247/16 =0 ?

The solution to x^2+5x+y^2-7y+247/16 =0 is Circle with (a,b)=(-5/2 , 7/2),r= 7/4

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x^2+5x+y^2-7y+247/16 =0

x^{2} + 5 x + y^{2} - 7 y + \frac{247}{16} = 0

(a, b) = (- \frac{5}{2}, \frac{7}{2}), r = \frac{7}{4}

Solution steps

x^{2} + 5 x + y^{2} - 7 y + \frac{247}{16} = 0

Rewrite

x^{2} + 5 x + y^{2} - 7 y + \frac{247}{16} = 0

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{7}{2})^{2} = (\frac{7}{4})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{7}{2}), r = \frac{7}{4}

(x - 5)^{(2)} + (y + 7)^{(2)} = 50

x^{2} - 16 x + 64 + y^{2} - 16 x = 0

x^{2} + y^{2} + 6 x - 4 y - 4 = 0

(x - 4)^{2} + (y + 3)^{2} = \frac{16}{9}

(x - 5)^{2} + (y + 2)^{2} = 61

What is x^2+5x+y^2-7y+247/16 =0 ?
The solution to x^2+5x+y^2-7y+247/16 =0 is Circle with (a,b)=(-5/2 , 7/2),r= 7/4