What is x^2+y^2-1=x ?

The solution to x^2+y^2-1=x is Circle with (a,b)=(1/2 ,0),r=(sqrt(5))/2

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x^2+y^2-1=x

x^{2} + y^{2} - 1 = x

(a, b) = (\frac{1}{2}, 0), r = \frac{5}{2}

Solution steps

x^{2} + y^{2} - 1 = x

Rewrite

x^{2} + y^{2} - 1 = x

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - 0)^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 0), r = \frac{5}{2}

3 x^{2} - 12 x + 3 y^{2} - 6 y - 12 = 0

x^{2} + y^{2} + 4 x + 10 y + 25 = 0

x^{2} + y^{2} + 2 x - 10 y - 4 = 0

x^{2} + y^{2} \geq 2 x

x^{2} + 4 x + y^{2} - 4 y = - 4

What is x^2+y^2-1=x ?
The solution to x^2+y^2-1=x is Circle with (a,b)=(1/2 ,0),r=(sqrt(5))/2