What is (x-11)^2+(y+8)^2=74 ?

The solution to (x-11)^2+(y+8)^2=74 is Circle with (a,b)=(11,-8),r=sqrt(74)

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(x-11)^2+(y+8)^2=74

(x - 11)^{2} + (y + 8)^{2} = 74

(a, b) = (11, - 8), r = 74

Solution steps

(x - 11)^{2} + (y + 8)^{2} = 74

Rewrite

(x - 11)^{2} + (y + 8)^{2} = 74

in the form of the standard circle equation

(x - 11)^{2} + (y - (- 8))^{2} = (74)^{2}

Therefore the circle properties are:

(a, b) = (11, - 8), r = 74

x^{2} + 2 x + y^{2} + 4 y - 6 = 0

x^{2} + y^{2} = 5625

4 x^{2} + 4 y^{2} + 12 x - 24 y + 29 = 0

x^{2} + (y + 4)^{2} = 18

(x - 4)^{2} + (y - (- 3))^{2} = 4^{2}

What is (x-11)^2+(y+8)^2=74 ?
The solution to (x-11)^2+(y+8)^2=74 is Circle with (a,b)=(11,-8),r=sqrt(74)