What is x^2-4x+y^2-8y=5 ?

The solution to x^2-4x+y^2-8y=5 is Circle with (a,b)=(2,4),r=5

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x^2-4x+y^2-8y=5

x^{2} - 4 x + y^{2} - 8 y = 5

(a, b) = (2, 4), r = 5

Solution steps

x^{2} - 4 x + y^{2} - 8 y = 5

Rewrite

x^{2} - 4 x + y^{2} - 8 y = 5

in the form of the standard circle equation

(x - 2)^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (2, 4), r = 5

y^{2} = - x^{2} - 2 x

x^{2} + y^{2} - 4 x + 2 y = - 4

x^{2} + y^{2} = (22)^{2}

(x - 1)^{2} + (y - 4)^{2} = 81

(x + \frac{1}{7})^{2} + (y - \frac{3}{5})^{2} = \frac{25}{9}

What is x^2-4x+y^2-8y=5 ?
The solution to x^2-4x+y^2-8y=5 is Circle with (a,b)=(2,4),r=5