What is (X+3)^2+(Y-0)^2=9^2 ?

The solution to (X+3)^2+(Y-0)^2=9^2 is Circle with (a,b)=(-3,0),r=9

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(X+3)^2+(Y-0)^2=9^2

(X + 3)^{2} + (Y - 0)^{2} = 9^{2}

(a, b) = (- 3, 0), r = 9

Solution steps

(X + 3)^{2} + (Y - 0)^{2} = 9^{2}

Rewrite

(X + 3)^{2} + (Y - 0)^{2} = 9^{2}

in the form of the standard circle equation

(X - (- 3))^{2} + (Y - 0)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 3, 0), r = 9

(5 - x)^{2} + z^{2} = 4

x^{2} + 2 x + y^{2} - 4 y - 4 = 0

(x + \frac{2}{3})^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} + 6 x - 10 y + 25 = 0

x^{2} + y^{2} + 4 x + 2 y - 11 = 0

What is (X+3)^2+(Y-0)^2=9^2 ?
The solution to (X+3)^2+(Y-0)^2=9^2 is Circle with (a,b)=(-3,0),r=9