What is (x-5)^2+(y-1)^2=49 ?

The solution to (x-5)^2+(y-1)^2=49 is Circle with (a,b)=(5,1),r=7

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(x-5)^2+(y-1)^2=49

(x - 5)^{2} + (y - 1)^{2} = 49

(a, b) = (5, 1), r = 7

Solution steps

(x - 5)^{2} + (y - 1)^{2} = 49

Rewrite

(x - 5)^{2} + (y - 1)^{2} = 49

in the form of the standard circle equation

(x - 5)^{2} + (y - 1)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (5, 1), r = 7

(x - 1)^{2} + (y + 5)^{2} = 25

x^{2} + y^{2} - \frac{12}{11} x - \frac{84}{11} y - \frac{640}{11} = 0

x^{2} + 8 x + y^{2} + 2 y + 13 = 0

x^{2} + y^{2} - 6 x + 4 y - 2 = 0

(x + \frac{5}{7})^{2} + (y + \frac{2}{7})^{2} = 8

What is (x-5)^2+(y-1)^2=49 ?
The solution to (x-5)^2+(y-1)^2=49 is Circle with (a,b)=(5,1),r=7