What is (x-2)^2+(y+4)^2=13.199^2 ?

The solution to (x-2)^2+(y+4)^2=13.199^2 is Circle with (a,b)=(2,-4),r=13.199

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(x-2)^2+(y+4)^2=13.199^2

(x - 2)^{2} + (y + 4)^{2} = 13.19 9^{2}

(a, b) = (2, - 4), r = 13.199

Solution steps

(x - 2)^{2} + (y + 4)^{2} = 13.19 9^{2}

Rewrite

(x - 2)^{2} + (y + 4)^{2} = 13.19 9^{2}

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 4))^{2} = 13.19 9^{2}

Therefore the circle properties are:

(a, b) = (2, - 4), r = 13.199

x^{2} + y^{2} - 16 x - 36 = 0

(x - 1)^{2} + (y + 1)^{2} = 16

(x - 5)^{2} + y^{2} = 106

x^{2} + 6 x + y^{2} - 27 = 0

(x + 1)^{2} + (y + 3)^{2} = 44.1

What is (x-2)^2+(y+4)^2=13.199^2 ?
The solution to (x-2)^2+(y+4)^2=13.199^2 is Circle with (a,b)=(2,-4),r=13.199