What is (x+1)^2+(y+6)^2=100 ?

The solution to (x+1)^2+(y+6)^2=100 is Circle with (a,b)=(-1,-6),r=10

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(x+1)^2+(y+6)^2=100

(x + 1)^{2} + (y + 6)^{2} = 100

(a, b) = (- 1, - 6), r = 10

Solution steps

(x + 1)^{2} + (y + 6)^{2} = 100

Rewrite

(x + 1)^{2} + (y + 6)^{2} = 100

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 6))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 6), r = 10

(x - 1)^{2} + (y + 2)^{2} = 1

x^{(2)} + y^{(2)} - 6 x + 4 y - 12 = 0

x^{2} + y^{2} + 12 x - 4 y + 31 = 0

(x - 6)^{2} + (y - 2)^{2} = 1 6^{2}

x^{2} + y^{2} + 6 x - 8 y - 15 = 0

What is (x+1)^2+(y+6)^2=100 ?
The solution to (x+1)^2+(y+6)^2=100 is Circle with (a,b)=(-1,-6),r=10