What is x^2+y^2-10x+8y=0 ?

The solution to x^2+y^2-10x+8y=0 is Circle with (a,b)=(5,-4),r=sqrt(41)

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x^2+y^2-10x+8y=0

x^{2} + y^{2} - 10 x + 8 y = 0

(a, b) = (5, - 4), r = 41

Solution steps

x^{2} + y^{2} - 10 x + 8 y = 0

Rewrite

x^{2} + y^{2} - 10 x + 8 y = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 4))^{2} = (41)^{2}

Therefore the circle properties are:

(a, b) = (5, - 4), r = 41

x^{2} + y^{2} - 4 x + 10 y + 20 = 0

3 (x + 1)^{(2)} + 3 (y - 1)^{(2)} = 6

x^{2} + y^{2} - 8 x + 10 y + 8 = 0

3 x^{2} + 3 y^{2} - 3 y + 6 x - 4 = 0

(x + 2)^{2} + (y + 4)^{2} = 2

What is x^2+y^2-10x+8y=0 ?
The solution to x^2+y^2-10x+8y=0 is Circle with (a,b)=(5,-4),r=sqrt(41)