What is 2x^2+2y^2+24x-36y+34=0 ?

The solution to 2x^2+2y^2+24x-36y+34=0 is Circle with (a,b)=(-6,9),r=10

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2x^2+2y^2+24x-36y+34=0

2 x^{2} + 2 y^{2} + 24 x - 36 y + 34 = 0

(a, b) = (- 6, 9), r = 10

Solution steps

2 x^{2} + 2 y^{2} + 24 x - 36 y + 34 = 0

Rewrite

2 x^{2} + 2 y^{2} + 24 x - 36 y + 34 = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 9)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 6, 9), r = 10

a^{2} + b^{2} = 30

(x - 3)^{2} + (y - 4)^{2} = 5

x^{2} + y^{2} - 4 x - 4 = 0

x^{2} + (y + 2)^{2} = 90

3 x^{2} + 3 y^{2} - 6 x + 9 y + 2 = 0

What is 2x^2+2y^2+24x-36y+34=0 ?
The solution to 2x^2+2y^2+24x-36y+34=0 is Circle with (a,b)=(-6,9),r=10