What is 2x^2+2y^2= 1/2 ?

The solution to 2x^2+2y^2= 1/2 is Circle with (a,b)=(0,0),r= 1/2

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2x^2+2y^2= 1/2

2 x^{2} + 2 y^{2} = \frac{1}{2}

(a, b) = (0, 0), r = \frac{1}{2}

Solution steps

2 x^{2} + 2 y^{2} = \frac{1}{2}

Rewrite

2 x^{2} + 2 y^{2} = \frac{1}{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{1}{2}

(x - 1)^{2} + (y - 1)^{2} = 1^{2}

2 x^{2} + 2 y^{2} - 20 x + 8 y + 34 = 0

3 x^{2} + 3 y^{2} - 12 x + 15 y = 21

(x - 4)^{2} + (y - 1)^{2} = 49

x^{2} + y^{2} - 32 x - 8 y + 264 = 0

What is 2x^2+2y^2= 1/2 ?
The solution to 2x^2+2y^2= 1/2 is Circle with (a,b)=(0,0),r= 1/2